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-3(1x+5)=3(1x+-1)
We move all terms to the left:
-3(1x+5)-(3(1x+-1))=0
We add all the numbers together, and all the variables
-3(x+5)-(3(x-1))=0
We multiply parentheses
-3x-(3(x-1))-15=0
We calculate terms in parentheses: -(3(x-1)), so:We get rid of parentheses
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
-3x-3x+3-15=0
We add all the numbers together, and all the variables
-6x-12=0
We move all terms containing x to the left, all other terms to the right
-6x=12
x=12/-6
x=-2
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