-3(11-k)=-3(k-1)

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Solution for -3(11-k)=-3(k-1) equation: 



-3(11-k)=-3(k-1)

We move all terms to the left:

-3(11-k)-(-3(k-1))=0

We add all the numbers together, and all the variables

-3(-1k+11)-(-3(k-1))=0

We multiply parentheses

3k-(-3(k-1))-33=0



We calculate terms in parentheses: -(-3(k-1)), so:

-3(k-1)

We multiply parentheses

-3k+3

Back to the equation:

-(-3k+3)



We get rid of parentheses

3k+3k-3-33=0

We add all the numbers together, and all the variables

6k-36=0

We move all terms containing k to the left, all other terms to the right

6k=36

k=36/6

k=6

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