-3(1-12c)=-11(1-3c)+7c

Solution for -3(1-12c)=-11(1-3c)+7c equation:

-3(1-12c)=-11(1-3c)+7c

We move all terms to the left:

-3(1-12c)-(-11(1-3c)+7c)=0

We add all the numbers together, and all the variables

-3(-12c+1)-(-11(-3c+1)+7c)=0

We multiply parentheses

36c-(-11(-3c+1)+7c)-3=0


We calculate terms in parentheses: -(-11(-3c+1)+7c), so:

-11(-3c+1)+7c

We add all the numbers together, and all the variables

7c-11(-3c+1)

We multiply parentheses

7c+33c-11

We add all the numbers together, and all the variables

40c-11

Back to the equation:

-(40c-11)


We get rid of parentheses

36c-40c+11-3=0

We add all the numbers together, and all the variables

-4c+8=0

We move all terms containing c to the left, all other terms to the right

-4c=-8

c=-8/-4

c=+2