-3(1+6r)=16-r

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Solution for -3(1+6r)=16-r equation: 



-3(1+6r)=16-r

We move all terms to the left:

-3(1+6r)-(16-r)=0

We add all the numbers together, and all the variables

-3(6r+1)-(-1r+16)=0

We multiply parentheses

-18r-(-1r+16)-3=0

We get rid of parentheses

-18r+1r-16-3=0

We add all the numbers together, and all the variables

-17r-19=0

We move all terms containing r to the left, all other terms to the right

-17r=19

r=19/-17

r=-1+2/17

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