-3(-9y+2)-8y=4(y-5)-4

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Solution for -3(-9y+2)-8y=4(y-5)-4 equation:



-3(-9y+2)-8y=4(y-5)-4
We move all terms to the left:
-3(-9y+2)-8y-(4(y-5)-4)=0
We add all the numbers together, and all the variables
-8y-3(-9y+2)-(4(y-5)-4)=0
We multiply parentheses
-8y+27y-(4(y-5)-4)-6=0
We calculate terms in parentheses: -(4(y-5)-4), so:
4(y-5)-4
We multiply parentheses
4y-20-4
We add all the numbers together, and all the variables
4y-24
Back to the equation:
-(4y-24)
We add all the numbers together, and all the variables
19y-(4y-24)-6=0
We get rid of parentheses
19y-4y+24-6=0
We add all the numbers together, and all the variables
15y+18=0
We move all terms containing y to the left, all other terms to the right
15y=-18
y=-18/15
y=-1+1/5

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