-3(-9-b)=1/3(b+33)

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Solution for -3(-9-b)=1/3(b+33) equation: 



-3(-9-b)=1/3(b+33)

We move all terms to the left:

-3(-9-b)-(1/3(b+33))=0



Domain of the equation: 3(b+33))!=0

b∈R



We add all the numbers together, and all the variables

-3(-1b-9)-(1/3(b+33))=0

We multiply parentheses

3b-(1/3(b+33))+27=0

We multiply all the terms by the denominator


3b*3(b+33))-(1+27*3(b+33))=0

Wy multiply elements

9b^2(b+81b(b=0

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