-3(-6-b)=1/3(b=6)

Solution for -3(-6-b)=1/3(b=6) equation:

-3(-6-b)=1/3(b=6)

We move all terms to the left:

-3(-6-b)-(1/3(b)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R


We add all the numbers together, and all the variables

-3(-1b-6)-(1/3b=0

We multiply parentheses

3b-(1/3b+18=0

We multiply all the terms by the denominator


3b*3b+18-(1=0

We add all the numbers together, and all the variables

3b*3b=0

Wy multiply elements

9b^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{18}=0$