-3((2/3y)-8)-6y=10

Solution for -3((2/3y)-8)-6y=10 equation:

-3((2/3y)-8)-6y=10

We move all terms to the left:

-3((2/3y)-8)-6y-(10)=0


Domain of the equation: 3y)-8)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-3((+2/3y)-8)-6y-10=0

We add all the numbers together, and all the variables

-6y-3((+2/3y)-8)-10=0

We multiply all the terms by the denominator


-6y*3y)-8)-3((-10*3y)-8)+2=0

Wy multiply elements

-18y^2-30y=0

a = -18; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·(-18)·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*-18}=\frac{0}{-36}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*-18}=\frac{60}{-36}
=-1+2/3
$