-2y-2+6=3(y+2)

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Solution for -2y-2+6=3(y+2) equation: 



-2y-2+6=3(y+2)

We move all terms to the left:

-2y-2+6-(3(y+2))=0

We add all the numbers together, and all the variables

-2y-(3(y+2))+4=0



We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)



We get rid of parentheses

-2y-3y-6+4=0

We add all the numbers together, and all the variables

-5y-2=0

We move all terms containing y to the left, all other terms to the right

-5y=2

y=2/-5

y=-2/5

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