-2y+40=-5(y-8)+3y

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Solution for -2y+40=-5(y-8)+3y equation:


Simplifying
-2y + 40 = -5(y + -8) + 3y

Reorder the terms:
40 + -2y = -5(y + -8) + 3y

Reorder the terms:
40 + -2y = -5(-8 + y) + 3y
40 + -2y = (-8 * -5 + y * -5) + 3y
40 + -2y = (40 + -5y) + 3y

Combine like terms: -5y + 3y = -2y
40 + -2y = 40 + -2y

Add '-40' to each side of the equation.
40 + -40 + -2y = 40 + -40 + -2y

Combine like terms: 40 + -40 = 0
0 + -2y = 40 + -40 + -2y
-2y = 40 + -40 + -2y

Combine like terms: 40 + -40 = 0
-2y = 0 + -2y
-2y = -2y

Add '2y' to each side of the equation.
-2y + 2y = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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