-2x2=-168

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Solution for -2x2=-168 equation:



-2x^2=-168
We move all terms to the left:
-2x^2-(-168)=0
We add all the numbers together, and all the variables
-2x^2+168=0
a = -2; b = 0; c = +168;
Δ = b2-4ac
Δ = 02-4·(-2)·168
Δ = 1344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1344}=\sqrt{64*21}=\sqrt{64}*\sqrt{21}=8\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{21}}{2*-2}=\frac{0-8\sqrt{21}}{-4} =-\frac{8\sqrt{21}}{-4} =-\frac{2\sqrt{21}}{-1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{21}}{2*-2}=\frac{0+8\sqrt{21}}{-4} =\frac{8\sqrt{21}}{-4} =\frac{2\sqrt{21}}{-1} $

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