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-2x^2+11x-2=0
a = -2; b = 11; c = -2;
Δ = b2-4ac
Δ = 112-4·(-2)·(-2)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{105}}{2*-2}=\frac{-11-\sqrt{105}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{105}}{2*-2}=\frac{-11+\sqrt{105}}{-4} $
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