-2x-5(2x-6)=3x-3(x-4)+6

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Solution for -2x-5(2x-6)=3x-3(x-4)+6 equation: 



-2x-5(2x-6)=3x-3(x-4)+6

We move all terms to the left:

-2x-5(2x-6)-(3x-3(x-4)+6)=0

We multiply parentheses

-2x-10x-(3x-3(x-4)+6)+30=0



We calculate terms in parentheses: -(3x-3(x-4)+6), so:

3x-3(x-4)+6

We multiply parentheses

3x-3x+12+6

We add all the numbers together, and all the variables

18

Back to the equation:

-(18)



We add all the numbers together, and all the variables

-12x+12=0

We move all terms containing x to the left, all other terms to the right

-12x=-12

x=-12/-12

x=1

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