-2x+4x-8=2(x-4)-4

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Solution for -2x+4x-8=2(x-4)-4 equation: 



-2x+4x-8=2(x-4)-4

We move all terms to the left:

-2x+4x-8-(2(x-4)-4)=0

We add all the numbers together, and all the variables

2x-(2(x-4)-4)-8=0



We calculate terms in parentheses: -(2(x-4)-4), so:

2(x-4)-4

We multiply parentheses

2x-8-4

We add all the numbers together, and all the variables

2x-12

Back to the equation:

-(2x-12)



We get rid of parentheses

2x-2x+12-8=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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