-2x+4=2x(4x-3)-3(-8+4x)

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Solution for -2x+4=2x(4x-3)-3(-8+4x) equation: 



-2x+4=2x(4x-3)-3(-8+4x)

We move all terms to the left:

-2x+4-(2x(4x-3)-3(-8+4x))=0

We add all the numbers together, and all the variables

-2x-(2x(4x-3)-3(4x-8))+4=0



We calculate terms in parentheses: -(2x(4x-3)-3(4x-8)), so:

2x(4x-3)-3(4x-8)

We multiply parentheses

8x^2-6x-12x+24

We add all the numbers together, and all the variables

8x^2-18x+24

Back to the equation:

-(8x^2-18x+24)



We get rid of parentheses

-8x^2-2x+18x-24+4=0

We add all the numbers together, and all the variables

-8x^2+16x-20=0

a = -8; b = 16; c = -20;
Δ = b2-4ac
Δ = 162-4·(-8)·(-20)
Δ = -384
Delta is less than zero, so there is no solution for the equation

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