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-2x+3=(-1/3)(6x-9)
We move all terms to the left:
-2x+3-((-1/3)(6x-9))=0
Domain of the equation: 3)(6x-9))!=0We multiply parentheses ..
x∈R
-((-6x^2-1/3*-9))-2x+3=0
We multiply all the terms by the denominator
-((-6x^2-1-2x*3*-9))+3*3*-9))=0
We calculate terms in parentheses: -((-6x^2-1-2x*3*-9)), so:We add all the numbers together, and all the variables
(-6x^2-1-2x*3*-9)
We get rid of parentheses
-6x^2-2x*3*-1-9
We add all the numbers together, and all the variables
-6x^2-2x*3*-10
Wy multiply elements
-6x^2-6x^2-10
We add all the numbers together, and all the variables
-12x^2-10
Back to the equation:
-(-12x^2-10)
-(-12x^2-10)=0
We get rid of parentheses
12x^2+10=0
a = 12; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·12·10
Δ = -480
Delta is less than zero, so there is no solution for the equation
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