-2x+2(1+x)=3(x-1)+8

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Solution for -2x+2(1+x)=3(x-1)+8 equation: 



-2x+2(1+x)=3(x-1)+8

We move all terms to the left:

-2x+2(1+x)-(3(x-1)+8)=0

We add all the numbers together, and all the variables

-2x+2(x+1)-(3(x-1)+8)=0

We multiply parentheses

-2x+2x-(3(x-1)+8)+2=0



We calculate terms in parentheses: -(3(x-1)+8), so:

3(x-1)+8

We multiply parentheses

3x-3+8

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

-(3x+5)+2=0

We get rid of parentheses

-3x-5+2=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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