-2x+10=x(-6x+30)

Solution for -2x+10=x(-6x+30) equation:

-2x+10=x(-6x+30)

We move all terms to the left:

-2x+10-(x(-6x+30))=0


We calculate terms in parentheses: -(x(-6x+30)), so:

x(-6x+30)

We multiply parentheses

-6x^2+30x

Back to the equation:

-(-6x^2+30x)


We get rid of parentheses

6x^2-30x-2x+10=0

We add all the numbers together, and all the variables

6x^2-32x+10=0

a = 6; b = -32; c = +10;
Δ = b2-4ac
Δ = -322-4·6·10
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-28}{2*6}=\frac{4}{12}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+28}{2*6}=\frac{60}{12}
=5
$