-2x(x-2)=3(x+2)

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Solution for -2x(x-2)=3(x+2) equation: 



-2x(x-2)=3(x+2)

We move all terms to the left:

-2x(x-2)-(3(x+2))=0

We multiply parentheses

-2x^2+4x-(3(x+2))=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

-2x^2+4x-3x-6=0

We add all the numbers together, and all the variables

-2x^2+x-6=0

a = -2; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·(-2)·(-6)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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