-2x(7x-8)+12x=4x+4

Solution for -2x(7x-8)+12x=4x+4 equation:

-2x(7x-8)+12x=4x+4

We move all terms to the left:

-2x(7x-8)+12x-(4x+4)=0

We add all the numbers together, and all the variables

12x-2x(7x-8)-(4x+4)=0

We multiply parentheses

-14x^2+12x+16x-(4x+4)=0

We get rid of parentheses

-14x^2+12x+16x-4x-4=0

We add all the numbers together, and all the variables

-14x^2+24x-4=0

a = -14; b = 24; c = -4;
Δ = b2-4ac
Δ = 242-4·(-14)·(-4)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{22}}{2*-14}=\frac{-24-4\sqrt{22}}{-28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{22}}{2*-14}=\frac{-24+4\sqrt{22}}{-28}
$