-2x(3x-5)=2x+10-8x

Solution for -2x(3x-5)=2x+10-8x equation:

-2x(3x-5)=2x+10-8x

We move all terms to the left:

-2x(3x-5)-(2x+10-8x)=0

We add all the numbers together, and all the variables

-2x(3x-5)-(-6x+10)=0

We multiply parentheses

-6x^2+10x-(-6x+10)=0

We get rid of parentheses

-6x^2+10x+6x-10=0

We add all the numbers together, and all the variables

-6x^2+16x-10=0

a = -6; b = 16; c = -10;
Δ = b2-4ac
Δ = 162-4·(-6)·(-10)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*-6}=\frac{-20}{-12}
=1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*-6}=\frac{-12}{-12}
=1
$