-2x(3x-4)=-4x

Solution for -2x(3x-4)=-4x equation:

-2x(3x-4)=-4x

We move all terms to the left:

-2x(3x-4)-(-4x)=0

We multiply parentheses

-6x^2+8x-(-4x)=0

We get rid of parentheses

-6x^2+8x+4x=0

We add all the numbers together, and all the variables

-6x^2+12x=0

a = -6; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-6)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-6}=\frac{-24}{-12}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-6}=\frac{0}{-12}
=0
$