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-2x(1x+1)=-2x+5
We move all terms to the left:
-2x(1x+1)-(-2x+5)=0
We add all the numbers together, and all the variables
-2x(x+1)-(-2x+5)=0
We multiply parentheses
-2x^2-2x-(-2x+5)=0
We get rid of parentheses
-2x^2-2x+2x-5=0
We add all the numbers together, and all the variables
-2x^2-5=0
a = -2; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-2)·(-5)
Δ = -40
Delta is less than zero, so there is no solution for the equation
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