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-2x^2+27x-41=0
a = -2; b = 27; c = -41;
Δ = b2-4ac
Δ = 272-4·(-2)·(-41)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{401}}{2*-2}=\frac{-27-\sqrt{401}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{401}}{2*-2}=\frac{-27+\sqrt{401}}{-4} $
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