-2r+8(r+2)=4(r-3)

Solution for -2r+8(r+2)=4(r-3) equation:

-2r+8(r+2)=4(r-3)

We move all terms to the left:

-2r+8(r+2)-(4(r-3))=0

We multiply parentheses

-2r+8r-(4(r-3))+16=0


We calculate terms in parentheses: -(4(r-3)), so:

4(r-3)

We multiply parentheses

4r-12

Back to the equation:

-(4r-12)


We add all the numbers together, and all the variables

6r-(4r-12)+16=0

We get rid of parentheses

6r-4r+12+16=0

We add all the numbers together, and all the variables

2r+28=0

We move all terms containing r to the left, all other terms to the right

2r=-28

r=-28/2

r=-14