-2r(1+4r)=8r(-r+4)=0

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Solution for -2r(1+4r)=8r(-r+4)=0 equation: 



-2r(1+4r)=8r(-r+4)=0

We move all terms to the left:

-2r(1+4r)-(8r(-r+4))=0

We add all the numbers together, and all the variables

-2r(4r+1)-(8r(-1r+4))=0

We multiply parentheses

-8r^2-2r-(8r(-1r+4))=0



We calculate terms in parentheses: -(8r(-1r+4)), so:

8r(-1r+4)

We multiply parentheses

-8r^2+32r

Back to the equation:

-(-8r^2+32r)



We get rid of parentheses

-8r^2+8r^2-32r-2r=0

We add all the numbers together, and all the variables

-34r=0

r=0/-34

r=0

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