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-2q^2+-9q+-4=0
We add all the numbers together, and all the variables
-2q^2-9q=0
a = -2; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-2)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-2}=\frac{0}{-4} =0 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-2}=\frac{18}{-4} =-4+1/2 $
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