-2k-5(1-k)=-k+27

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Solution for -2k-5(1-k)=-k+27 equation: 



-2k-5(1-k)=-k+27

We move all terms to the left:

-2k-5(1-k)-(-k+27)=0

We add all the numbers together, and all the variables

-2k-5(-1k+1)-(-1k+27)=0

We multiply parentheses

-2k+5k-(-1k+27)-5=0

We get rid of parentheses

-2k+5k+1k-27-5=0

We add all the numbers together, and all the variables

4k-32=0

We move all terms containing k to the left, all other terms to the right

4k=32

k=32/4

k=8

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