-2g(-3g-5)=28

Solution for -2g(-3g-5)=28 equation:

-2g(-3g-5)=28

We move all terms to the left:

-2g(-3g-5)-(28)=0

We multiply parentheses

6g^2+10g-28=0

a = 6; b = 10; c = -28;
Δ = b2-4ac
Δ = 102-4·6·(-28)
Δ = 772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{772}=\sqrt{4*193}=\sqrt{4}*\sqrt{193}=2\sqrt{193}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{193}}{2*6}=\frac{-10-2\sqrt{193}}{12}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{193}}{2*6}=\frac{-10+2\sqrt{193}}{12}
$