-2f(f+9)=-18f+

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Solution for -2f(f+9)=-18f+ equation: 



-2f(f+9)=-18f+

We move all terms to the left:

-2f(f+9)-(-18f+)=0

We add all the numbers together, and all the variables

-2f(f+9)-(-18f)=0

We multiply parentheses

-2f^2-18f-(-18f)=0

We get rid of parentheses

-2f^2-18f+18f=0

We add all the numbers together, and all the variables

-2f^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{0}{-4}=0$

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