-2b-28=2(b-6)

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Solution for -2b-28=2(b-6) equation: 



-2b-28=2(b-6)

We move all terms to the left:

-2b-28-(2(b-6))=0



We calculate terms in parentheses: -(2(b-6)), so:

2(b-6)

We multiply parentheses

2b-12

Back to the equation:

-(2b-12)



We get rid of parentheses

-2b-2b+12-28=0

We add all the numbers together, and all the variables

-4b-16=0

We move all terms containing b to the left, all other terms to the right

-4b=16

b=16/-4

b=-4

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