-2b+2(b+5)=7+3(11-5b)

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Solution for -2b+2(b+5)=7+3(11-5b) equation:



-2b+2(b+5)=7+3(11-5b)
We move all terms to the left:
-2b+2(b+5)-(7+3(11-5b))=0
We add all the numbers together, and all the variables
-2b+2(b+5)-(7+3(-5b+11))=0
We multiply parentheses
-2b+2b-(7+3(-5b+11))+10=0
We calculate terms in parentheses: -(7+3(-5b+11)), so:
7+3(-5b+11)
determiningTheFunctionDomain 3(-5b+11)+7
We multiply parentheses
-15b+33+7
We add all the numbers together, and all the variables
-15b+40
Back to the equation:
-(-15b+40)
We add all the numbers together, and all the variables
-(-15b+40)+10=0
We get rid of parentheses
15b-40+10=0
We add all the numbers together, and all the variables
15b-30=0
We move all terms containing b to the left, all other terms to the right
15b=30
b=30/15
b=2

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