-2a+3(4a-5)=75

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Solution for -2a+3(4a-5)=75 equation: 



-2a+3(4a-5)=75

We move all terms to the left:

-2a+3(4a-5)-(75)=0

We multiply parentheses

-2a+12a-15-75=0

We add all the numbers together, and all the variables

10a-90=0

We move all terms containing a to the left, all other terms to the right

10a=90

a=90/10

a=9

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