-292=2-6(1+6v)

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Solution for -292=2-6(1+6v) equation: 



-292=2-6(1+6v)

We move all terms to the left:

-292-(2-6(1+6v))=0

We add all the numbers together, and all the variables

-(2-6(6v+1))-292=0



We calculate terms in parentheses: -(2-6(6v+1)), so:

2-6(6v+1)

determiningTheFunctionDomain
-6(6v+1)+2

We multiply parentheses

-36v-6+2

We add all the numbers together, and all the variables

-36v-4

Back to the equation:

-(-36v-4)



We get rid of parentheses

36v+4-292=0

We add all the numbers together, and all the variables

36v-288=0

We move all terms containing v to the left, all other terms to the right

36v=288

v=288/36

v=8

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