-28=4(y+3)-8y

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Solution for -28=4(y+3)-8y equation: 



-28=4(y+3)-8y

We move all terms to the left:

-28-(4(y+3)-8y)=0



We calculate terms in parentheses: -(4(y+3)-8y), so:

4(y+3)-8y

We add all the numbers together, and all the variables

-8y+4(y+3)

We multiply parentheses

-8y+4y+12

We add all the numbers together, and all the variables

-4y+12

Back to the equation:

-(-4y+12)



We get rid of parentheses

4y-12-28=0

We add all the numbers together, and all the variables

4y-40=0

We move all terms containing y to the left, all other terms to the right

4y=40

y=40/4

y=10

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