-28=2+4(b-3)

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Solution for -28=2+4(b-3) equation: 



-28=2+4(b-3)

We move all terms to the left:

-28-(2+4(b-3))=0



We calculate terms in parentheses: -(2+4(b-3)), so:

2+4(b-3)

determiningTheFunctionDomain
4(b-3)+2

We multiply parentheses

4b-12+2

We add all the numbers together, and all the variables

4b-10

Back to the equation:

-(4b-10)



We get rid of parentheses

-4b+10-28=0

We add all the numbers together, and all the variables

-4b-18=0

We move all terms containing b to the left, all other terms to the right

-4b=18

b=18/-4

b=-4+1/2

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