-28=2(4f+2)=4

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Solution for -28=2(4f+2)=4 equation: 



-28=2(4f+2)=4

We move all terms to the left:

-28-(2(4f+2))=0



We calculate terms in parentheses: -(2(4f+2)), so:

2(4f+2)

We multiply parentheses

8f+4

Back to the equation:

-(8f+4)



We get rid of parentheses

-8f-4-28=0

We add all the numbers together, and all the variables

-8f-32=0

We move all terms containing f to the left, all other terms to the right

-8f=32

f=32/-8

f=-4

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