-28-2n=2(2n-5)

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Solution for -28-2n=2(2n-5) equation: 



-28-2n=2(2n-5)

We move all terms to the left:

-28-2n-(2(2n-5))=0



We calculate terms in parentheses: -(2(2n-5)), so:

2(2n-5)

We multiply parentheses

4n-10

Back to the equation:

-(4n-10)



We get rid of parentheses

-2n-4n+10-28=0

We add all the numbers together, and all the variables

-6n-18=0

We move all terms containing n to the left, all other terms to the right

-6n=18

n=18/-6

n=-3

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