-28+4x=5(2x-2)

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Solution for -28+4x=5(2x-2) equation: 



-28+4x=5(2x-2)

We move all terms to the left:

-28+4x-(5(2x-2))=0



We calculate terms in parentheses: -(5(2x-2)), so:

5(2x-2)

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)



We get rid of parentheses

4x-10x+10-28=0

We add all the numbers together, and all the variables

-6x-18=0

We move all terms containing x to the left, all other terms to the right

-6x=18

x=18/-6

x=-3

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