-26-(2y+2)=2(y-2)+4y

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Solution for -26-(2y+2)=2(y-2)+4y equation:



-26-(2y+2)=2(y-2)+4y
We move all terms to the left:
-26-(2y+2)-(2(y-2)+4y)=0
We get rid of parentheses
-2y-(2(y-2)+4y)-2-26=0
We calculate terms in parentheses: -(2(y-2)+4y), so:
2(y-2)+4y
We add all the numbers together, and all the variables
4y+2(y-2)
We multiply parentheses
4y+2y-4
We add all the numbers together, and all the variables
6y-4
Back to the equation:
-(6y-4)
We add all the numbers together, and all the variables
-2y-(6y-4)-28=0
We get rid of parentheses
-2y-6y+4-28=0
We add all the numbers together, and all the variables
-8y-24=0
We move all terms containing y to the left, all other terms to the right
-8y=24
y=24/-8
y=-3

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