-26+b=4(1+3b)-b

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Solution for -26+b=4(1+3b)-b equation: 



-26+b=4(1+3b)-b

We move all terms to the left:

-26+b-(4(1+3b)-b)=0

We add all the numbers together, and all the variables

b-(4(3b+1)-b)-26=0



We calculate terms in parentheses: -(4(3b+1)-b), so:

4(3b+1)-b

We add all the numbers together, and all the variables

-1b+4(3b+1)

We multiply parentheses

-1b+12b+4

We add all the numbers together, and all the variables

11b+4

Back to the equation:

-(11b+4)



We get rid of parentheses

b-11b-4-26=0

We add all the numbers together, and all the variables

-10b-30=0

We move all terms containing b to the left, all other terms to the right

-10b=30

b=30/-10

b=-3

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