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-25=1/5h=5
We move all terms to the left:
-25-(1/5h)=0
Domain of the equation: 5h)!=0We add all the numbers together, and all the variables
h!=0/1
h!=0
h∈R
-(+1/5h)-25=0
We get rid of parentheses
-1/5h-25=0
We multiply all the terms by the denominator
-25*5h-1=0
Wy multiply elements
-125h-1=0
We move all terms containing h to the left, all other terms to the right
-125h=1
h=1/-125
h=-1/125
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