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-25=1/2(10x-2)-+3x
We move all terms to the left:
-25-(1/2(10x-2)-+3x)=0
Domain of the equation: 2(10x-2)-+3x)!=0We use the square of the difference formula
x∈R
-(1/2(10x-2)-3x)-25=0
We multiply all the terms by the denominator
-(1-25*2(10x-2)-3x)=0
We calculate terms in parentheses: -(1-25*2(10x-2)-3x), so:We add all the numbers together, and all the variables
1-25*2(10x-2)-3x
determiningTheFunctionDomain -25*2(10x-2)-3x+1
We add all the numbers together, and all the variables
-3x-25*2(10x-2)+1
Wy multiply elements
-3x-50x(1+1
Back to the equation:
-(-3x-50x(1+1)
-(-3x-50x2=0
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