-24-2b=3(-4b+4)+4b

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Solution for -24-2b=3(-4b+4)+4b equation: 



-24-2b=3(-4b+4)+4b

We move all terms to the left:

-24-2b-(3(-4b+4)+4b)=0



We calculate terms in parentheses: -(3(-4b+4)+4b), so:

3(-4b+4)+4b

We add all the numbers together, and all the variables

4b+3(-4b+4)

We multiply parentheses

4b-12b+12

We add all the numbers together, and all the variables

-8b+12

Back to the equation:

-(-8b+12)



We get rid of parentheses

-2b+8b-12-24=0

We add all the numbers together, and all the variables

6b-36=0

We move all terms containing b to the left, all other terms to the right

6b=36

b=36/6

b=6

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