-24+12f=2(f-3)+22

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Solution for -24+12f=2(f-3)+22 equation: 



-24+12f=2(f-3)+22

We move all terms to the left:

-24+12f-(2(f-3)+22)=0



We calculate terms in parentheses: -(2(f-3)+22), so:

2(f-3)+22

We multiply parentheses

2f-6+22

We add all the numbers together, and all the variables

2f+16

Back to the equation:

-(2f+16)



We get rid of parentheses

12f-2f-16-24=0

We add all the numbers together, and all the variables

10f-40=0

We move all terms containing f to the left, all other terms to the right

10f=40

f=40/10

f=4

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