-24+12d=2d(d-3)+22

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Solution for -24+12d=2d(d-3)+22 equation: 



-24+12d=2d(d-3)+22

We move all terms to the left:

-24+12d-(2d(d-3)+22)=0



We calculate terms in parentheses: -(2d(d-3)+22), so:

2d(d-3)+22

We multiply parentheses

2d^2-6d+22

Back to the equation:

-(2d^2-6d+22)



We get rid of parentheses

-2d^2+12d+6d-22-24=0

We add all the numbers together, and all the variables

-2d^2+18d-46=0

a = -2; b = 18; c = -46;
Δ = b2-4ac
Δ = 182-4·(-2)·(-46)
Δ = -44
Delta is less than zero, so there is no solution for the equation

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