-22=6+(2/3)x

Solution for -22=6+(2/3)x equation:

-22=6+(2/3)x

We move all terms to the left:

-22-(6+(2/3)x)=0


Domain of the equation: 3)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(6+(+2/3)x)-22=0

We multiply all the terms by the denominator


-(6+(+2-22*3)x)=0


We calculate terms in parentheses: -(6+(+2-22*3)x), so:

6+(+2-22*3)x

determiningTheFunctionDomain
(+2-22*3)x+6

We add all the numbers together, and all the variables

(-64)x+6

We multiply parentheses

-64x+6

Back to the equation:

-(-64x+6)


We get rid of parentheses

64x-6=0

We move all terms containing x to the left, all other terms to the right

64x=6

x=6/64

x=3/32