-22=4(v-4)+2v

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Solution for -22=4(v-4)+2v equation: 



-22=4(v-4)+2v

We move all terms to the left:

-22-(4(v-4)+2v)=0



We calculate terms in parentheses: -(4(v-4)+2v), so:

4(v-4)+2v

We add all the numbers together, and all the variables

2v+4(v-4)

We multiply parentheses

2v+4v-16

We add all the numbers together, and all the variables

6v-16

Back to the equation:

-(6v-16)



We get rid of parentheses

-6v+16-22=0

We add all the numbers together, and all the variables

-6v-6=0

We move all terms containing v to the left, all other terms to the right

-6v=6

v=6/-6

v=-1

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