-22=-4(-4+3n)+2(n-2)

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Solution for -22=-4(-4+3n)+2(n-2) equation: 



-22=-4(-4+3n)+2(n-2)

We move all terms to the left:

-22-(-4(-4+3n)+2(n-2))=0

We add all the numbers together, and all the variables

-(-4(3n-4)+2(n-2))-22=0



We calculate terms in parentheses: -(-4(3n-4)+2(n-2)), so:

-4(3n-4)+2(n-2)

We multiply parentheses

-12n+2n+16-4

We add all the numbers together, and all the variables

-10n+12

Back to the equation:

-(-10n+12)



We get rid of parentheses

10n-12-22=0

We add all the numbers together, and all the variables

10n-34=0

We move all terms containing n to the left, all other terms to the right

10n=34

n=34/10

n=3+2/5

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