-21x-3(6x+11)=-4(3x-8)-3x+26x+40

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Solution for -21x-3(6x+11)=-4(3x-8)-3x+26x+40 equation:



-21x-3(6x+11)=-4(3x-8)-3x+26x+40
We move all terms to the left:
-21x-3(6x+11)-(-4(3x-8)-3x+26x+40)=0
We multiply parentheses
-21x-18x-(-4(3x-8)-3x+26x+40)-33=0
We calculate terms in parentheses: -(-4(3x-8)-3x+26x+40), so:
-4(3x-8)-3x+26x+40
We add all the numbers together, and all the variables
23x-4(3x-8)+40
We multiply parentheses
23x-12x+32+40
We add all the numbers together, and all the variables
11x+72
Back to the equation:
-(11x+72)
We add all the numbers together, and all the variables
-39x-(11x+72)-33=0
We get rid of parentheses
-39x-11x-72-33=0
We add all the numbers together, and all the variables
-50x-105=0
We move all terms containing x to the left, all other terms to the right
-50x=105
x=105/-50
x=-2+1/10

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